Dropbox API Python

[AdanHerrera]

Hello,

Please I need help, How can I do this with Business API

import dropbox

client = dropbox.Dropbox('JCJoqsBi2DAAAAGGHFHFGH')

for entry in client.files_list_folder('').entries:
print(entry)

[Greg-DB · Accepted solution]

If you have a Dropbox Business API app with the "team member file access" permission, and want to use a user-specific API call, such as files_list_folder, you can do so using DropboxTeam.as_user.

First, you should make your DropboxTeam instance, and then use DropboxTeam.as_user to get a Dropbox instance. You can then use that Dropbox instance normally for user API calls. That would look like this:

import dropbox

TEAM_MEMBER_FILE_ACCESS_ACCESS_TOKEN = '...'
TEAM_MEMBER_ID = 'dbmid:...'

team_client = dropbox.DropboxTeam(TEAM_MEMBER_FILE_ACCESS_ACCESS_TOKEN)
user_client = team_client.as_user(TEAM_MEMBER_ID)

for entry in user_client.files_list_folder('').entries:
    print(entry)

You can get the member ID for the desired member from the Dropbox Business API, in a TeamMemberInfo, e.g., as returned by team_members_list/team_members_list_continue or team_members_get_info, etc.

[AdanHerrera]

Can you show me show to do this: "You can get the member ID for the desired member from the Dropbox Business API, in a TeamMemberInfo, e.g., as returned by team_members_list/team_members_list_continue or team_members_get_info, etc."

I'm a rookie and I'm a little lost... thanks

[Greg-DB · Accepted solution]

That would look like this, for example:

team_member_info = team_client.team_members_get_info([dropbox.team.UserSelectorArg.email(member_email_address)]).pop()
if team_member_info and team_member_info.is_member_info():
    team_member_id = team_member_info.get_member_info().profile.team_member_id