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aplowman's avatar
aplowman
Explorer | Level 4
5 years ago
Solved

Malformed authorize_url returned from DropboxOAuth2FlowNoRedirect.start() Python API

I am trying to use the `DropboxOAuth2FlowNoRedirect` example in the Python class docstring. It looks like this:

 

from dropbox import DropboxOAuth2FlowNoRedirect

auth_flow = DropboxOAuth2FlowNoRedirect(APP_KEY, APP_SECRET)

authorize_url = auth_flow.start()
print("1. Go to: " + authorize_url)
print("2. Click \\"Allow\\" (you might have to log in first).")
print("3. Copy the authorization code.")
auth_code = raw_input("Enter the authorization code here: ").strip()

try:
    oauth_result = auth_flow.finish(auth_code)
except Exception as e:
    print('Error: %s' % (e,))
    return

dbx = Dropbox(oauth_result.access_token)

The resulting `authorize_url` seems to be malformed: it includes "&" instead of just "&", meaning when navigating to it, Dropbox returns an error: unknown field "amp". Is this a bug or am I doing something wrong?

 

Thanks

API

3 Replies

  • Greg-DB's avatar
    Greg-DB
    Icon for Dropbox Community Moderator rankDropbox Community Moderator
    5 years ago

    Thanks for the report. This issue doesn't seem to reproduce for me though. To help us investigate, can you share:

    • the version of the Dropbox Python library you have installed
    • the version of Python you're using
    • the full output you get
  • aplowman's avatar
    aplowman
    Explorer | Level 4
    5 years ago

    Ah. It is something to do with Jupyter Lab. The URL is fine in the iPython REPL and in Jupyter notebook. I am using the Python dropbox package version 10.1.1 and Python 3.8.2.

     

    If I run this code:

     

    from dropbox import DropboxOAuth2FlowNoRedirect, Dropbox

auth_flow = DropboxOAuth2FlowNoRedirect(APP_KEY, APP_SECRET)
authorize_url = auth_flow.start()

print("1. Go to: " + authorize_url)
print("2. Click \"Allow\" (you might have to log in first).")
print("3. Copy the authorization code.")

auth_code = input("Enter the authorization code here: ").strip()
try:
    oauth_result = auth_flow.finish(auth_code)
except Exception as e:
    print('Error: %s' % (e,))

dbx = Dropbox(oauth_result.access_token)

    in a cell within Jupyter Lab, I get the following output (with client ID removed):

     

     

  • Greg-DB's avatar
    Greg-DB
    Icon for Dropbox Community Moderator rankDropbox Community Moderator
    5 years ago

    I see, thanks for the information! 

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