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mark2mark
7 years agoHelpful | Level 7
multiple calls of `files_get_temporary_link`
Hello, I just got stuck when trying to call dbx.files_get_temporary_link(path) multiple times in python. because I need to create a bunch of links for a dynamically fed input (different paths...
- 7 years ago
Well, if you uncomment the second call, and hence have both ones running, it doesnāt work anymore at my side. With the exact code I posted before.
Is that what you also tried, too? You said »both calls, each generating a unique link to the same file.« but it should be two different files. Just saying.
Now that I wanted to create a simplified version of the code for you, this one actually works. It is very weird though, because it aināt too different from my actual code. Iāll post the now working one here (maybe also as a refernece for others). But I still donāt understand why my other code doesnāt work.#!/usr/bin/env python # -*- coding: utf-8 -*- import dropbox import os import traceback access_token = '*****' dbx = dropbox.Dropbox(access_token) def getTemporaryLink(dbx, folder, name): path = '/%s/%s' % (folder, name) try: link = dbx.files_get_temporary_link(path) except dropbox.exceptions.HttpError as err: print '*** HTTP error', err return None return link products = ["One.zip", "Two.zip"] temporaryLinks = [] for product in products: x = getTemporaryLink(dbx, "myFolder", product) temporaryLinks.append(x) for linkResult in temporaryLinks: print linkResult.link
chirstius
Dropbox Staff
7 years agoHey mark2mark,
From the sample you have provided, you are correct, there's nothing technically wrong with the call to get_temporary_link(), but the issue seems to revolve around what is being done to the result that comes back (a GetTemporaryLinkResult object).
Would you be willing to post a bit more of your code to help identify what might be causing this? Particularly what's being done with the result of the call.
Thanks!
-Chuck
- mark2mark7 years agoHelpful | Level 7
Wow chirstius, what a quick reply. Thank you!
hereās a basic code.Thanks in advance!
#!/usr/bin/env python # -*- coding: utf-8 -*- import dropbox import os access_token = "*****" dbx = dropbox.Dropbox(access_token) def getTemporaryLink(dbx, folder, name): path = '/%s/%s' % (folder, name) try: link = dbx.files_get_temporary_link(path) except dropbox.exceptions.HttpError as err: print '*** HTTP error', err return None return link folder = "myFirstLevelFolder" temporaryLink1 = getTemporaryLink(dbx, folder, "thing1.zip") print temporaryLink1 # WORKS up to here.
# temporaryLink2 = getTemporaryLink(dbx, folder, "thing2.zip") # breaks, throws error # print temporaryLink2- chirstius7 years ago
Dropbox Staff
Thanks for posting. I was able to run your code and it seems to work without error - both calls, each generating a unique link to the same file.
The error you are seeing would seem to imply trying to invoke a method call directly on the results object (or a property of it). This code isn't doing anything beyond printing the results. Can you show some of the original code as-is and let's see if we can figure out what might be going wrong there?
Thanks!
-Chuck
- mark2mark7 years agoHelpful | Level 7
Well, if you uncomment the second call, and hence have both ones running, it doesnāt work anymore at my side. With the exact code I posted before.
Is that what you also tried, too? You said »both calls, each generating a unique link to the same file.« but it should be two different files. Just saying.
Now that I wanted to create a simplified version of the code for you, this one actually works. It is very weird though, because it aināt too different from my actual code. Iāll post the now working one here (maybe also as a refernece for others). But I still donāt understand why my other code doesnāt work.#!/usr/bin/env python # -*- coding: utf-8 -*- import dropbox import os import traceback access_token = '*****' dbx = dropbox.Dropbox(access_token) def getTemporaryLink(dbx, folder, name): path = '/%s/%s' % (folder, name) try: link = dbx.files_get_temporary_link(path) except dropbox.exceptions.HttpError as err: print '*** HTTP error', err return None return link products = ["One.zip", "Two.zip"] temporaryLinks = [] for product in products: x = getTemporaryLink(dbx, "myFolder", product) temporaryLinks.append(x) for linkResult in temporaryLinks: print linkResult.link
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