How to programmatically get the Authorization code without requiring the user approval in OAuth

[chemical21]

I´d like get the autorization code without being prompted out of my application.

I think the listener are about listem to process

why not just get redirected parameters code and state from a plain text result?

I saw a question about 

// Handle OAuth redirect and send URL fragment to local server using JS.
await HandleOAuth2Redirect(http);

it keep waiting forever. 

I see the code I want at the page that prompted me on navigator e I dont know what am I waiting for or what do must to do.

for the exmaple I use never takes heare:

// Handle redirect from JS and process OAuth response.
var redirectUri_ = await HandleJSRedirect(http);

Doesnt matter if is for once, it is note going good. 

I got a applicaton same objective of this one working on google drive by using pkcs file with credentials.

It work so easy to me. There is another procedure like this up I mentioned?

[Greg-DB]

I'm not sure I fully understand all of your questions, so feel free to follow up and clarify. I've also split out your message here to a new thread so as not to bother the members of the old thread.

It's not possible to get an authorization code without processing the app authorization flow. The user needs to authorize the app at least once in order for the app to be able to access the user's account. That authorization process occurs on the Dropbox web site.

The Dropbox .NET SDK implements much of the app authorization flow for you, and offers example code, but use of the SDK is optional. If you don't want to or can't use it for your use case or environment for whatever reason, you can use the Dropbox API directly without the SDK. You can find information on implementing the authorization flow directly in the OAuth Guide and authorization documentation. That does have to be implemented as documented though; Dropbox doesn't offer a way to use a certificate/PKCS file and apps shouldn't handle user credentials (like the username/password) themselves.